>Try not to be controversial. Not 100% electricity is turned into heat. A small fraction of the electricity is turned into magnetic field<
Okay. For my own curiosity, what % of the electricity are we talking about with an AC heater than ends up as a magnetic field? 0.1%, 1%, 10%?
That's a good question. Without knowing the resistance/thermal resistance/coil diamter/number of turns of the heater, it's very difficult to estimate.
And you don't need ferrite core to generate the magnetic field. The purpose of ferrite is to serve as a reservoir of magnetic field. In this case, you really do not want to use ferrite in the heater core because it will reduce the amount of electricity converted into the thermal energy.
In the electrical engineering world, we call it Q factor.
Q = 2*pi*f*L/R.
where f is the operating frequency, L is the inductance, and R is the resistance.
Q factor represents the ratio of the energy stored versus energy dissipated when the electrical field passes a given device. In our heater application, we want a low Q device, i.e. minimum magnetic energy gets stored in the coil, and maximum electric energy gets dissipated, which is in this case turns into heat. Adding the ferrite to the core will only elevate the Q factor.
MarkO is right, we are talking about pennies here.
Actually, I got this crazy idea: what we should really do is to design a water proof case to hold the metal Hallide ballast then drop it in the tank. It would turn into a natural heater. Once the water temperature hits the target, you raise the ballast from the water. With some clever mechanical robot design, we can even automate it. The problem is that it won't work at all during the halide down time. Anyway, just a thought.